The winning Wisconsin Pick 3 numbers for December 6, 1999 were: single 4-2-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 6, 1999 | Single | 4-2-2 | 8 | 8 |
| Dec 5, 1999 | Single | 6-4-2 | 12 | 3 |
| Dec 4, 1999 | Single | 4-4-9 | 17 | 8 |
| Dec 3, 1999 | Single | 5-5-1 | 11 | 2 |
| Dec 2, 1999 | Single | 2-2-9 | 13 | 4 |
| Dec 1, 1999 | Single | 5-6-3 | 14 | 5 |
| Nov 30, 1999 | Single | 7-4-2 | 13 | 4 |