The winning Washington DC DC-4 numbers for December 11, 1996 were: evening 5-5-4-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 11, 1996 | Evening | 5-5-4-1 | 15 | 6 |
| Dec 10, 1996 | Evening | 0-2-7-0 | 9 | 9 |
| Dec 9, 1996 | Midday | 7-5-8-7 | 27 | 9 |
| Dec 8, 1996 | Evening | 6-2-5-4 | 17 | 8 |
| Dec 7, 1996 | Evening | 4-8-8-0 | 20 | 2 |
| Dec 7, 1996 | Midday | 6-7-4-3 | 20 | 2 |
| Dec 6, 1996 | Evening | 9-9-3-0 | 21 | 3 |
| Dec 6, 1996 | Midday | 5-5-8-5 | 23 | 5 |
| Dec 5, 1996 | Evening | 9-4-1-2 | 16 | 7 |
| Dec 5, 1996 | Midday | 8-6-8-6 | 28 | 1 |