The winning Washington DC DC-3 numbers for December 5, 1993 were: evening 8-6-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 5, 1993 | Evening | 8-6-3 | 17 | 8 |
| Dec 4, 1993 | Midday | 7-6-8 | 21 | 3 |
| Dec 3, 1993 | Evening | 0-6-8 | 14 | 5 |
| Dec 3, 1993 | Midday | 2-9-2 | 13 | 4 |
| Dec 2, 1993 | Evening | 8-0-3 | 11 | 2 |
| Dec 2, 1993 | Midday | 3-9-9 | 21 | 3 |
| Dec 1, 1993 | Evening | 8-3-1 | 12 | 3 |
| Dec 1, 1993 | Midday | 2-0-2 | 4 | 4 |
| Nov 30, 1993 | Evening | 8-6-4 | 18 | 9 |
| Nov 30, 1993 | Midday | 8-3-2 | 13 | 4 |
| Nov 29, 1993 | Midday | 5-7-0 | 12 | 3 |