The winning Washington DC DC-3 numbers for November 5, 1990 were: single 3-7-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 5, 1990 | Single | 3-7-2 | 12 | 3 |
| Nov 2, 1990 | Single | 8-8-0 | 16 | 7 |
| Oct 31, 1990 | Single | 9-2-8 | 19 | 1 |