The winning Virginia Pick 4 numbers for December 26, 2003 were: day 4-2-6-8; night 2-1-0-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 26, 2003 | Night | 2-1-0-4 | 7 | 7 |
| Dec 26, 2003 | Day | 4-2-6-8 | 20 | 2 |
| Dec 25, 2003 | Night | 8-4-6-5 | 23 | 5 |
| Dec 25, 2003 | Day | 4-8-8-0 | 20 | 2 |
| Dec 24, 2003 | Night | 9-7-5-5 | 26 | 8 |
| Dec 24, 2003 | Day | 8-1-2-9 | 20 | 2 |
| Dec 23, 2003 | Night | 6-3-5-0 | 14 | 5 |
| Dec 23, 2003 | Day | 5-9-9-4 | 27 | 9 |
| Dec 22, 2003 | Night | 8-0-6-0 | 14 | 5 |
| Dec 22, 2003 | Day | 5-1-5-5 | 16 | 7 |
| Dec 20, 2003 | Night | 7-0-2-3 | 12 | 3 |
| Dec 20, 2003 | Day | 9-5-2-5 | 21 | 3 |