The winning Virginia Pick 4 numbers for December 2, 2003 were: day 4-5-9-5; night 5-0-3-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 2, 2003 | Night | 5-0-3-7 | 15 | 6 |
| Dec 2, 2003 | Day | 4-5-9-5 | 23 | 5 |
| Dec 1, 2003 | Night | 4-9-2-0 | 15 | 6 |
| Dec 1, 2003 | Day | 7-5-9-3 | 24 | 6 |
| Nov 29, 2003 | Night | 6-8-8-9 | 31 | 4 |
| Nov 29, 2003 | Day | 2-2-8-0 | 12 | 3 |
| Nov 28, 2003 | Night | 0-2-2-3 | 7 | 7 |
| Nov 28, 2003 | Day | 8-2-4-8 | 22 | 4 |
| Nov 27, 2003 | Night | 9-2-2-0 | 13 | 4 |
| Nov 27, 2003 | Day | 8-8-5-3 | 24 | 6 |
| Nov 26, 2003 | Night | 6-0-6-4 | 16 | 7 |
| Nov 26, 2003 | Day | 8-3-9-9 | 29 | 2 |