The winning Virginia Pick 4 numbers for September 12, 2003 were: day 7-3-2-4; night 0-6-7-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 12, 2003 | Night | 0-6-7-1 | 14 | 5 |
| Sep 12, 2003 | Day | 7-3-2-4 | 16 | 7 |
| Sep 11, 2003 | Night | 9-2-7-8 | 26 | 8 |
| Sep 11, 2003 | Day | 1-4-1-7 | 13 | 4 |
| Sep 10, 2003 | Night | 5-9-3-1 | 18 | 9 |
| Sep 10, 2003 | Day | 9-0-8-6 | 23 | 5 |
| Sep 9, 2003 | Night | 5-5-9-0 | 19 | 1 |
| Sep 9, 2003 | Day | 8-4-5-0 | 17 | 8 |
| Sep 8, 2003 | Night | 9-5-5-4 | 23 | 5 |
| Sep 8, 2003 | Day | 0-5-9-9 | 23 | 5 |
| Sep 6, 2003 | Night | 2-7-8-7 | 24 | 6 |
| Sep 6, 2003 | Day | 7-1-7-0 | 15 | 6 |