The winning Virginia Pick 4 numbers for December 7, 2002 were: day 9-8-8-2; night 7-5-6-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 7, 2002 | Night | 7-5-6-2 | 20 | 2 |
| Dec 7, 2002 | Day | 9-8-8-2 | 27 | 9 |
| Dec 6, 2002 | Night | 6-7-1-9 | 23 | 5 |
| Dec 6, 2002 | Day | 1-9-4-5 | 19 | 1 |
| Dec 5, 2002 | Night | 6-4-4-1 | 15 | 6 |
| Dec 5, 2002 | Day | 4-3-7-5 | 19 | 1 |
| Dec 4, 2002 | Night | 6-3-0-7 | 16 | 7 |
| Dec 4, 2002 | Day | 5-0-8-1 | 14 | 5 |
| Dec 3, 2002 | Night | 1-9-8-0 | 18 | 9 |
| Dec 3, 2002 | Day | 1-4-8-4 | 17 | 8 |
| Dec 2, 2002 | Night | 5-4-3-6 | 18 | 9 |
| Dec 2, 2002 | Day | 5-3-9-4 | 21 | 3 |