The winning Virginia Pick 4 numbers for December 4, 2002 were: day 5-0-8-1; night 6-3-0-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 4, 2002 | Night | 6-3-0-7 | 16 | 7 |
| Dec 4, 2002 | Day | 5-0-8-1 | 14 | 5 |
| Dec 3, 2002 | Night | 1-9-8-0 | 18 | 9 |
| Dec 3, 2002 | Day | 1-4-8-4 | 17 | 8 |
| Dec 2, 2002 | Night | 5-4-3-6 | 18 | 9 |
| Dec 2, 2002 | Day | 5-3-9-4 | 21 | 3 |
| Nov 30, 2002 | Night | 5-9-5-6 | 25 | 7 |
| Nov 30, 2002 | Day | 9-3-1-9 | 22 | 4 |
| Nov 29, 2002 | Night | 2-2-8-8 | 20 | 2 |
| Nov 29, 2002 | Day | 2-9-9-6 | 26 | 8 |
| Nov 28, 2002 | Night | 5-2-1-1 | 9 | 9 |
| Nov 28, 2002 | Day | 0-0-7-4 | 11 | 2 |