The winning Virginia Pick 4 numbers for December 16, 1999 were: day 9-6-3-8; night 7-7-7-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 16, 1999 | Night | 7-7-7-6 | 27 | 9 |
| Dec 16, 1999 | Day | 9-6-3-8 | 26 | 8 |
| Dec 15, 1999 | Night | 3-6-2-3 | 14 | 5 |
| Dec 15, 1999 | Day | 3-1-6-0 | 10 | 1 |
| Dec 14, 1999 | Night | 4-5-6-5 | 20 | 2 |
| Dec 14, 1999 | Day | 3-9-0-2 | 14 | 5 |
| Dec 13, 1999 | Night | 2-3-0-4 | 9 | 9 |
| Dec 13, 1999 | Day | 2-2-5-0 | 9 | 9 |
| Dec 11, 1999 | Night | 3-1-9-5 | 18 | 9 |
| Dec 11, 1999 | Day | 1-7-1-6 | 15 | 6 |
| Dec 10, 1999 | Night | 1-9-4-3 | 17 | 8 |
| Dec 10, 1999 | Day | 0-6-7-0 | 13 | 4 |