The winning Virginia Pick 4 numbers for October 22, 1999 were: day 6-2-4-7; night 0-5-5-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 22, 1999 | Night | 0-5-5-7 | 17 | 8 |
| Oct 22, 1999 | Day | 6-2-4-7 | 19 | 1 |
| Oct 21, 1999 | Night | 7-3-3-1 | 14 | 5 |
| Oct 21, 1999 | Day | 9-7-6-6 | 28 | 1 |
| Oct 20, 1999 | Night | 7-4-8-6 | 25 | 7 |
| Oct 20, 1999 | Day | 1-3-4-6 | 14 | 5 |
| Oct 19, 1999 | Night | 7-1-2-6 | 16 | 7 |
| Oct 19, 1999 | Day | 0-0-0-1 | 1 | 1 |
| Oct 18, 1999 | Night | 4-1-3-3 | 11 | 2 |
| Oct 18, 1999 | Day | 4-6-9-0 | 19 | 1 |
| Oct 16, 1999 | Night | 2-6-2-6 | 16 | 7 |
| Oct 16, 1999 | Day | 4-7-8-4 | 23 | 5 |