The winning Virginia Pick 4 numbers for October 5, 1999 were: day 3-6-0-3; night 6-8-1-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 5, 1999 | Night | 6-8-1-1 | 16 | 7 |
| Oct 5, 1999 | Day | 3-6-0-3 | 12 | 3 |
| Oct 4, 1999 | Night | 6-4-9-8 | 27 | 9 |
| Oct 4, 1999 | Day | 4-3-0-4 | 11 | 2 |
| Oct 2, 1999 | Night | 7-1-9-2 | 19 | 1 |
| Oct 2, 1999 | Day | 3-7-5-3 | 18 | 9 |
| Oct 1, 1999 | Night | 0-3-2-9 | 14 | 5 |
| Oct 1, 1999 | Day | 8-3-1-3 | 15 | 6 |
| Sep 30, 1999 | Night | 1-6-3-4 | 14 | 5 |
| Sep 30, 1999 | Day | 2-3-6-6 | 17 | 8 |
| Sep 29, 1999 | Night | 9-6-4-2 | 21 | 3 |
| Sep 29, 1999 | Day | 1-8-3-8 | 20 | 2 |