The winning Virginia Pick 4 numbers for September 18, 1999 were: day 9-9-9-5; night 3-9-8-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 18, 1999 | Night | 3-9-8-8 | 28 | 1 |
| Sep 18, 1999 | Day | 9-9-9-5 | 32 | 5 |
| Sep 17, 1999 | Night | 8-6-4-6 | 24 | 6 |
| Sep 17, 1999 | Day | 6-3-6-9 | 24 | 6 |
| Sep 16, 1999 | Night | 2-1-8-4 | 15 | 6 |
| Sep 16, 1999 | Day | 9-7-7-6 | 29 | 2 |
| Sep 15, 1999 | Night | 2-8-7-1 | 18 | 9 |
| Sep 15, 1999 | Day | 2-7-8-9 | 26 | 8 |
| Sep 14, 1999 | Night | 5-2-4-5 | 16 | 7 |
| Sep 14, 1999 | Day | 8-4-8-0 | 20 | 2 |
| Sep 13, 1999 | Night | 6-4-8-6 | 24 | 6 |
| Sep 13, 1999 | Day | 2-1-5-1 | 9 | 9 |