The winning Virginia Pick 4 numbers for September 11, 1999 were: day 9-9-4-5; night 0-1-3-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 11, 1999 | Night | 0-1-3-2 | 6 | 6 |
| Sep 11, 1999 | Day | 9-9-4-5 | 27 | 9 |
| Sep 10, 1999 | Night | 9-8-5-4 | 26 | 8 |
| Sep 10, 1999 | Day | 8-6-3-7 | 24 | 6 |
| Sep 9, 1999 | Night | 4-4-0-9 | 17 | 8 |
| Sep 9, 1999 | Day | 7-9-2-9 | 27 | 9 |
| Sep 8, 1999 | Night | 5-3-6-1 | 15 | 6 |
| Sep 8, 1999 | Day | 2-3-2-1 | 8 | 8 |
| Sep 7, 1999 | Night | 0-1-9-1 | 11 | 2 |
| Sep 7, 1999 | Day | 3-5-9-5 | 22 | 4 |
| Sep 6, 1999 | Night | 6-8-6-0 | 20 | 2 |
| Sep 6, 1999 | Day | 7-6-3-0 | 16 | 7 |