The winning Virginia Pick 4 numbers for September 9, 1999 were: day 7-9-2-9; night 4-4-0-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 9, 1999 | Night | 4-4-0-9 | 17 | 8 |
| Sep 9, 1999 | Day | 7-9-2-9 | 27 | 9 |
| Sep 8, 1999 | Night | 5-3-6-1 | 15 | 6 |
| Sep 8, 1999 | Day | 2-3-2-1 | 8 | 8 |
| Sep 7, 1999 | Night | 0-1-9-1 | 11 | 2 |
| Sep 7, 1999 | Day | 3-5-9-5 | 22 | 4 |
| Sep 6, 1999 | Night | 6-8-6-0 | 20 | 2 |
| Sep 6, 1999 | Day | 7-6-3-0 | 16 | 7 |
| Sep 4, 1999 | Night | 3-1-6-3 | 13 | 4 |
| Sep 4, 1999 | Day | 1-5-8-9 | 23 | 5 |
| Sep 3, 1999 | Night | 1-1-6-0 | 8 | 8 |
| Sep 3, 1999 | Day | 1-6-4-8 | 19 | 1 |