The winning Virginia Pick 4 numbers for December 9, 1996 were: day 7-3-1-5; night 1-7-9-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 9, 1996 | Night | 1-7-9-3 | 20 | 2 |
| Dec 9, 1996 | Day | 7-3-1-5 | 16 | 7 |
| Dec 7, 1996 | Night | 3-2-5-7 | 17 | 8 |
| Dec 7, 1996 | Day | 0-5-2-2 | 9 | 9 |
| Dec 6, 1996 | Night | 4-4-7-4 | 19 | 1 |
| Dec 6, 1996 | Day | 1-7-5-5 | 18 | 9 |
| Dec 5, 1996 | Night | 6-5-1-7 | 19 | 1 |
| Dec 5, 1996 | Day | 5-7-2-4 | 18 | 9 |
| Dec 4, 1996 | Night | 2-1-7-1 | 11 | 2 |
| Dec 4, 1996 | Day | 0-5-9-8 | 22 | 4 |
| Dec 3, 1996 | Night | 1-1-3-2 | 7 | 7 |
| Dec 3, 1996 | Day | 9-6-5-4 | 24 | 6 |