The winning Virginia Pick 4 numbers for October 27, 1993 were: night 9-1-5-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 27, 1993 | Night | 9-1-5-3 | 18 | 9 |
| Oct 26, 1993 | Night | 7-1-6-8 | 22 | 4 |
| Oct 25, 1993 | Night | 9-9-7-4 | 29 | 2 |
| Oct 23, 1993 | Night | 1-9-3-2 | 15 | 6 |
| Oct 22, 1993 | Night | 8-6-7-2 | 23 | 5 |
| Oct 21, 1993 | Night | 2-0-7-4 | 13 | 4 |