The winning Virginia Pick 4 numbers for October 14, 1993 were: night 8-0-5-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 14, 1993 | Night | 8-0-5-8 | 21 | 3 |
| Oct 13, 1993 | Night | 9-8-7-4 | 28 | 1 |
| Oct 12, 1993 | Night | 5-0-0-6 | 11 | 2 |
| Oct 11, 1993 | Night | 7-2-8-9 | 26 | 8 |
| Oct 9, 1993 | Night | 4-9-6-0 | 19 | 1 |
| Oct 8, 1993 | Night | 6-0-5-7 | 18 | 9 |