The winning Virginia Pick 4 numbers for September 14, 1993 were: night 5-0-4-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 14, 1993 | Night | 5-0-4-2 | 11 | 2 |
| Sep 13, 1993 | Night | 0-8-7-4 | 19 | 1 |
| Sep 11, 1993 | Night | 6-8-1-0 | 15 | 6 |
| Sep 10, 1993 | Night | 6-7-2-1 | 16 | 7 |
| Sep 9, 1993 | Night | 5-1-9-6 | 21 | 3 |
| Sep 8, 1993 | Night | 5-7-6-7 | 25 | 7 |