The winning Virginia Pick 4 numbers for September 2, 1993 were: night 9-0-8-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 2, 1993 | Night | 9-0-8-8 | 25 | 7 |
| Sep 1, 1993 | Night | 8-3-5-6 | 22 | 4 |
| Aug 31, 1993 | Night | 9-2-8-2 | 21 | 3 |
| Aug 30, 1993 | Night | 3-5-3-0 | 11 | 2 |
| Aug 28, 1993 | Night | 3-2-4-0 | 9 | 9 |
| Aug 27, 1993 | Night | 4-7-4-9 | 24 | 6 |