The winning Virginia Pick 4 numbers for August 17, 1993 were: night 9-5-7-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 17, 1993 | Night | 9-5-7-7 | 28 | 1 |
| Aug 16, 1993 | Night | 3-8-8-1 | 20 | 2 |
| Aug 14, 1993 | Night | 6-3-4-0 | 13 | 4 |
| Aug 13, 1993 | Night | 0-8-9-3 | 20 | 2 |
| Aug 12, 1993 | Night | 0-1-0-9 | 10 | 1 |
| Aug 11, 1993 | Night | 1-8-8-4 | 21 | 3 |