The winning Virginia Pick 4 numbers for August 11, 1993 were: night 1-8-8-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 11, 1993 | Night | 1-8-8-4 | 21 | 3 |
| Aug 10, 1993 | Night | 8-3-1-9 | 21 | 3 |
| Aug 9, 1993 | Night | 7-5-0-7 | 19 | 1 |
| Aug 7, 1993 | Night | 9-8-7-3 | 27 | 9 |
| Aug 6, 1993 | Night | 5-0-1-7 | 13 | 4 |
| Aug 5, 1993 | Night | 7-1-6-7 | 21 | 3 |