The winning Virginia Pick 4 numbers for August 6, 1993 were: night 5-0-1-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 6, 1993 | Night | 5-0-1-7 | 13 | 4 |
| Aug 5, 1993 | Night | 7-1-6-7 | 21 | 3 |
| Aug 4, 1993 | Night | 7-8-0-8 | 23 | 5 |
| Aug 3, 1993 | Night | 0-8-6-1 | 15 | 6 |
| Aug 2, 1993 | Night | 5-7-8-3 | 23 | 5 |
| Jul 31, 1993 | Night | 9-9-2-4 | 24 | 6 |