The winning Virginia Pick 4 numbers for November 28, 1992 were: night 0-5-6-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 28, 1992 | Night | 0-5-6-2 | 13 | 4 |
| Nov 27, 1992 | Night | 3-2-6-7 | 18 | 9 |
| Nov 26, 1992 | Night | 7-8-7-6 | 28 | 1 |
| Nov 25, 1992 | Night | 5-3-8-7 | 23 | 5 |
| Nov 24, 1992 | Night | 9-0-2-2 | 13 | 4 |
| Nov 23, 1992 | Night | 6-9-5-7 | 27 | 9 |