The winning Virginia Pick 4 numbers for January 4, 1992 were: night 9-9-5-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jan 4, 1992 | Night | 9-9-5-5 | 28 | 1 |
| Jan 3, 1992 | Night | 5-3-3-6 | 17 | 8 |
| Jan 2, 1992 | Night | 6-0-3-7 | 16 | 7 |
| Jan 1, 1992 | Night | 2-6-6-6 | 20 | 2 |
| Dec 31, 1991 | Night | 1-7-2-1 | 11 | 2 |
| Dec 30, 1991 | Night | 3-9-1-4 | 17 | 8 |