The winning Virginia Pick 4 numbers for December 28, 1991 were: night 3-0-4-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 28, 1991 | Night | 3-0-4-7 | 14 | 5 |
| Dec 27, 1991 | Night | 5-6-0-1 | 12 | 3 |
| Dec 26, 1991 | Night | 4-5-6-3 | 18 | 9 |
| Dec 24, 1991 | Night | 6-8-2-3 | 19 | 1 |
| Dec 23, 1991 | Night | 7-0-4-1 | 12 | 3 |