The winning Virginia Pick 4 numbers for December 2, 1991 were: night 4-0-5-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 2, 1991 | Night | 4-0-5-0 | 9 | 9 |
| Nov 30, 1991 | Night | 2-6-0-4 | 12 | 3 |
| Nov 29, 1991 | Night | 4-8-9-0 | 21 | 3 |
| Nov 28, 1991 | Night | 7-2-1-3 | 13 | 4 |
| Nov 27, 1991 | Night | 3-9-2-1 | 15 | 6 |
| Nov 26, 1991 | Night | 5-4-1-1 | 11 | 2 |