The winning Virginia Pick 4 numbers for October 5, 1991 were: night 2-5-7-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 5, 1991 | Night | 2-5-7-1 | 15 | 6 |
| Oct 4, 1991 | Night | 8-9-4-7 | 28 | 1 |
| Oct 3, 1991 | Night | 1-1-8-0 | 10 | 1 |
| Oct 2, 1991 | Night | 3-1-5-3 | 12 | 3 |
| Oct 1, 1991 | Night | 5-1-5-3 | 14 | 5 |
| Sep 30, 1991 | Night | 3-3-4-5 | 15 | 6 |