The winning Virginia Pick 3 numbers for December 4, 2006 were: day 5-2-5; night 8-8-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 4, 2006 | Night | 8-8-0 | 16 | 7 |
| Dec 4, 2006 | Day | 5-2-5 | 12 | 3 |
| Dec 2, 2006 | Night | 5-0-3 | 8 | 8 |
| Dec 2, 2006 | Day | 5-6-9 | 20 | 2 |
| Dec 1, 2006 | Night | 6-1-7 | 14 | 5 |
| Dec 1, 2006 | Day | 8-2-1 | 11 | 2 |
| Nov 30, 2006 | Night | 2-1-2 | 5 | 5 |
| Nov 30, 2006 | Day | 3-9-0 | 12 | 3 |
| Nov 29, 2006 | Night | 3-5-3 | 11 | 2 |
| Nov 29, 2006 | Day | 1-6-8 | 15 | 6 |
| Nov 28, 2006 | Night | 3-5-4 | 12 | 3 |
| Nov 28, 2006 | Day | 4-2-4 | 10 | 1 |