The winning Virginia Pick 3 numbers for December 6, 2003 were: day 5-0-0; night 4-2-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 6, 2003 | Night | 4-2-5 | 11 | 2 |
| Dec 6, 2003 | Day | 5-0-0 | 5 | 5 |
| Dec 5, 2003 | Night | 7-6-9 | 22 | 4 |
| Dec 5, 2003 | Day | 5-6-1 | 12 | 3 |
| Dec 4, 2003 | Night | 1-4-9 | 14 | 5 |
| Dec 4, 2003 | Day | 1-9-0 | 10 | 1 |
| Dec 3, 2003 | Night | 0-9-2 | 11 | 2 |
| Dec 3, 2003 | Day | 7-1-5 | 13 | 4 |
| Dec 2, 2003 | Night | 6-3-1 | 10 | 1 |
| Dec 2, 2003 | Day | 1-9-3 | 13 | 4 |
| Dec 1, 2003 | Night | 7-1-0 | 8 | 8 |
| Dec 1, 2003 | Day | 9-2-5 | 16 | 7 |