The winning Virginia Pick 3 numbers for December 5, 2002 were: day 7-2-2; night 0-6-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 5, 2002 | Night | 0-6-7 | 13 | 4 |
| Dec 5, 2002 | Day | 7-2-2 | 11 | 2 |
| Dec 4, 2002 | Night | 4-9-7 | 20 | 2 |
| Dec 4, 2002 | Day | 1-8-0 | 9 | 9 |
| Dec 3, 2002 | Night | 7-2-9 | 18 | 9 |
| Dec 3, 2002 | Day | 0-8-9 | 17 | 8 |
| Dec 2, 2002 | Night | 0-4-4 | 8 | 8 |
| Dec 2, 2002 | Day | 9-7-1 | 17 | 8 |
| Nov 30, 2002 | Night | 2-5-9 | 16 | 7 |
| Nov 30, 2002 | Day | 5-3-7 | 15 | 6 |
| Nov 29, 2002 | Night | 5-3-7 | 15 | 6 |
| Nov 29, 2002 | Day | 5-8-0 | 13 | 4 |