The winning Virginia Pick 3 numbers for November 7, 2002 were: day 4-9-4; night 9-1-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 7, 2002 | Night | 9-1-5 | 15 | 6 |
| Nov 7, 2002 | Day | 4-9-4 | 17 | 8 |
| Nov 6, 2002 | Night | 7-3-4 | 14 | 5 |
| Nov 6, 2002 | Day | 7-1-7 | 15 | 6 |
| Nov 5, 2002 | Night | 6-8-2 | 16 | 7 |
| Nov 5, 2002 | Day | 1-0-9 | 10 | 1 |
| Nov 4, 2002 | Night | 7-5-5 | 17 | 8 |
| Nov 4, 2002 | Day | 5-7-2 | 14 | 5 |
| Nov 2, 2002 | Night | 9-5-9 | 23 | 5 |
| Nov 2, 2002 | Day | 8-0-9 | 17 | 8 |
| Nov 1, 2002 | Night | 7-3-7 | 17 | 8 |
| Nov 1, 2002 | Day | 4-2-6 | 12 | 3 |