The winning Virginia Pick 3 numbers for December 18, 1993 were: night 5-1-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 18, 1993 | Night | 5-1-9 | 15 | 6 |
| Dec 17, 1993 | Night | 9-2-5 | 16 | 7 |
| Dec 16, 1993 | Night | 3-6-4 | 13 | 4 |
| Dec 15, 1993 | Night | 9-9-5 | 23 | 5 |
| Dec 14, 1993 | Night | 6-9-7 | 22 | 4 |
| Dec 13, 1993 | Night | 4-1-7 | 12 | 3 |