The winning Virginia Pick 3 numbers for June 5, 1993 were: night 0-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jun 5, 1993 | Night | 0-7-0 | 7 | 7 |
| Jun 4, 1993 | Night | 1-0-6 | 7 | 7 |
| Jun 3, 1993 | Night | 5-7-4 | 16 | 7 |
| Jun 2, 1993 | Night | 9-2-4 | 15 | 6 |
| Jun 1, 1993 | Night | 2-5-3 | 10 | 1 |
| May 31, 1993 | Night | 3-8-9 | 20 | 2 |