The winning Virginia Pick 3 numbers for December 1, 1989 were: night 1-9-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 1, 1989 | Night | 1-9-0 | 10 | 1 |
| Nov 30, 1989 | Night | 3-5-5 | 13 | 4 |
| Nov 29, 1989 | Night | 4-5-1 | 10 | 1 |
| Nov 28, 1989 | Night | 3-5-3 | 11 | 2 |
| Nov 27, 1989 | Night | 5-7-0 | 12 | 3 |
| Nov 25, 1989 | Night | 9-7-3 | 19 | 1 |