The winning Virginia Pick 3 numbers for October 11, 1989 were: night 7-7-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 11, 1989 | Night | 7-7-7 | 21 | 3 |
| Oct 10, 1989 | Night | 8-7-0 | 15 | 6 |
| Oct 9, 1989 | Night | 0-6-4 | 10 | 1 |
| Oct 7, 1989 | Night | 6-5-7 | 18 | 9 |
| Oct 6, 1989 | Night | 4-7-6 | 17 | 8 |
| Oct 5, 1989 | Night | 5-0-2 | 7 | 7 |