The winning Virginia Pick 3 numbers for October 5, 1989 were: night 5-0-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 5, 1989 | Night | 5-0-2 | 7 | 7 |
| Oct 4, 1989 | Night | 2-5-6 | 13 | 4 |
| Oct 3, 1989 | Night | 6-3-2 | 11 | 2 |
| Oct 2, 1989 | Night | 5-5-7 | 17 | 8 |
| Sep 30, 1989 | Night | 7-3-0 | 10 | 1 |
| Sep 29, 1989 | Night | 0-3-5 | 8 | 8 |