The winning Vermont Pick 4 numbers for December 12, 2019 were: day 6-8-5-0; evening 8-2-3-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 12, 2019 | Evening | 8-2-3-0 | 13 | 4 |
| Dec 12, 2019 | Day | 6-8-5-0 | 19 | 1 |
| Dec 11, 2019 | Evening | 6-9-3-3 | 21 | 3 |
| Dec 11, 2019 | Day | 3-8-7-0 | 18 | 9 |
| Dec 10, 2019 | Evening | 0-7-1-7 | 15 | 6 |
| Dec 10, 2019 | Day | 6-3-9-3 | 21 | 3 |
| Dec 9, 2019 | Evening | 4-5-1-6 | 16 | 7 |
| Dec 9, 2019 | Day | 9-9-4-1 | 23 | 5 |
| Dec 8, 2019 | Evening | 4-7-2-9 | 22 | 4 |
| Dec 8, 2019 | Day | 3-3-9-6 | 21 | 3 |
| Dec 7, 2019 | Evening | 9-4-6-4 | 23 | 5 |
| Dec 7, 2019 | Day | 1-7-3-4 | 15 | 6 |
| Dec 6, 2019 | Evening | 1-9-4-9 | 23 | 5 |
| Dec 6, 2019 | Day | 8-8-5-8 | 29 | 2 |