The winning Vermont Pick 4 numbers for December 9, 2006 were: day 1-0-5-5; evening 9-7-5-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 9, 2006 | Evening | 9-7-5-0 | 21 | 3 |
| Dec 9, 2006 | Day | 1-0-5-5 | 11 | 2 |
| Dec 8, 2006 | Evening | 3-9-1-7 | 20 | 2 |
| Dec 8, 2006 | Day | 0-8-1-4 | 13 | 4 |
| Dec 7, 2006 | Evening | 8-4-3-1 | 16 | 7 |
| Dec 7, 2006 | Day | 9-4-1-9 | 23 | 5 |
| Dec 6, 2006 | Evening | 3-8-1-2 | 14 | 5 |
| Dec 6, 2006 | Day | 6-9-0-6 | 21 | 3 |
| Dec 5, 2006 | Evening | 8-4-1-7 | 20 | 2 |
| Dec 5, 2006 | Day | 3-8-7-1 | 19 | 1 |
| Dec 4, 2006 | Evening | 3-8-9-2 | 22 | 4 |
| Dec 4, 2006 | Day | 0-1-4-3 | 8 | 8 |
| Dec 3, 2006 | Evening | 3-3-1-9 | 16 | 7 |
| Dec 3, 2006 | Day | 5-8-9-6 | 28 | 1 |