The winning Vermont Pick 4 numbers for September 22, 2005 were: day 3-6-2-6; evening 9-1-5-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 22, 2005 | Evening | 9-1-5-0 | 15 | 6 |
| Sep 22, 2005 | Day | 3-6-2-6 | 17 | 8 |
| Sep 21, 2005 | Evening | 2-2-2-4 | 10 | 1 |
| Sep 21, 2005 | Day | 3-1-6-1 | 11 | 2 |
| Sep 20, 2005 | Evening | 8-1-3-0 | 12 | 3 |
| Sep 20, 2005 | Day | 6-1-5-3 | 15 | 6 |
| Sep 19, 2005 | Evening | 8-2-2-7 | 19 | 1 |
| Sep 19, 2005 | Day | 9-9-1-2 | 21 | 3 |
| Sep 18, 2005 | Evening | 1-2-8-2 | 13 | 4 |
| Sep 18, 2005 | Day | 7-3-0-5 | 15 | 6 |
| Sep 17, 2005 | Evening | 1-7-4-6 | 18 | 9 |
| Sep 17, 2005 | Day | 1-3-3-8 | 15 | 6 |
| Sep 16, 2005 | Evening | 7-3-0-0 | 10 | 1 |
| Sep 16, 2005 | Day | 1-3-3-3 | 10 | 1 |