The winning Vermont Pick 4 numbers for September 12, 2005 were: day 2-2-8-4; evening 9-6-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 12, 2005 | Evening | 9-6-7-0 | 22 | 4 |
| Sep 12, 2005 | Day | 2-2-8-4 | 16 | 7 |
| Sep 11, 2005 | Evening | 0-3-4-9 | 16 | 7 |
| Sep 11, 2005 | Day | 4-6-7-5 | 22 | 4 |
| Sep 10, 2005 | Evening | 7-3-7-9 | 26 | 8 |
| Sep 10, 2005 | Day | 3-6-9-1 | 19 | 1 |
| Sep 9, 2005 | Evening | 4-9-3-5 | 21 | 3 |
| Sep 9, 2005 | Day | 9-0-6-6 | 21 | 3 |
| Sep 8, 2005 | Evening | 5-7-7-3 | 22 | 4 |
| Sep 8, 2005 | Day | 2-9-8-7 | 26 | 8 |
| Sep 7, 2005 | Evening | 9-1-5-6 | 21 | 3 |
| Sep 7, 2005 | Day | 0-8-3-6 | 17 | 8 |
| Sep 6, 2005 | Evening | 0-7-9-9 | 25 | 7 |
| Sep 6, 2005 | Day | 7-6-0-7 | 20 | 2 |