The winning Vermont Pick 4 numbers for December 5, 2003 were: day 7-6-7-3; evening 2-1-5-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 5, 2003 | Evening | 2-1-5-5 | 13 | 4 |
| Dec 5, 2003 | Day | 7-6-7-3 | 23 | 5 |
| Dec 4, 2003 | Evening | 3-1-4-9 | 17 | 8 |
| Dec 4, 2003 | Day | 0-7-2-6 | 15 | 6 |
| Dec 3, 2003 | Evening | 0-5-9-7 | 21 | 3 |
| Dec 3, 2003 | Day | 2-0-4-8 | 14 | 5 |
| Dec 2, 2003 | Evening | 7-7-4-2 | 20 | 2 |
| Dec 2, 2003 | Day | 9-7-0-1 | 17 | 8 |
| Dec 1, 2003 | Evening | 7-2-2-2 | 13 | 4 |
| Dec 1, 2003 | Day | 5-5-5-3 | 18 | 9 |
| Nov 30, 2003 | Evening | 5-4-4-5 | 18 | 9 |
| Nov 30, 2003 | Day | 0-4-7-8 | 19 | 1 |
| Nov 29, 2003 | Evening | 6-8-2-2 | 18 | 9 |
| Nov 29, 2003 | Day | 4-9-0-6 | 19 | 1 |