The winning Vermont Pick 4 numbers for September 7, 1996 were: day 1-6-6-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 7, 1996 | Day | 1-6-6-3 | 16 | 7 |
| Sep 6, 1996 | Day | 2-3-4-2 | 11 | 2 |
| Sep 5, 1996 | Day | 3-1-0-7 | 11 | 2 |
| Sep 4, 1996 | Day | 1-3-5-3 | 12 | 3 |
| Sep 3, 1996 | Day | 3-5-9-2 | 19 | 1 |
| Sep 2, 1996 | Day | 8-7-0-8 | 23 | 5 |