The winning Vermont Pick 4 numbers for August 7, 1989 were: day 9-6-3-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 7, 1989 | Day | 9-6-3-7 | 25 | 7 |
| Aug 5, 1989 | Day | 3-4-6-0 | 13 | 4 |
| Aug 4, 1989 | Day | 8-2-4-5 | 19 | 1 |
| Aug 3, 1989 | Day | 5-3-0-5 | 13 | 4 |
| Aug 2, 1989 | Day | 3-9-3-1 | 16 | 7 |
| Aug 1, 1989 | Day | 3-9-0-5 | 17 | 8 |