The winning Vermont Pick 3 numbers for September 17, 2009 were: day 1-4-7; evening 9-1-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 17, 2009 | Evening | 9-1-4 | 14 | 5 |
| Sep 17, 2009 | Day | 1-4-7 | 12 | 3 |
| Sep 16, 2009 | Evening | 4-1-8 | 13 | 4 |
| Sep 16, 2009 | Day | 4-0-5 | 9 | 9 |
| Sep 15, 2009 | Evening | 3-7-3 | 13 | 4 |
| Sep 15, 2009 | Day | 6-0-1 | 7 | 7 |
| Sep 14, 2009 | Evening | 1-9-0 | 10 | 1 |
| Sep 14, 2009 | Day | 5-1-4 | 10 | 1 |
| Sep 13, 2009 | Evening | 6-7-4 | 17 | 8 |
| Sep 13, 2009 | Day | 1-6-4 | 11 | 2 |
| Sep 12, 2009 | Evening | 8-9-7 | 24 | 6 |
| Sep 12, 2009 | Day | 3-2-3 | 8 | 8 |
| Sep 11, 2009 | Evening | 0-8-8 | 16 | 7 |
| Sep 11, 2009 | Day | 9-9-4 | 22 | 4 |