The winning Vermont Pick 3 numbers for September 7, 2002 were: day 8-1-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 7, 2002 | Day | 8-1-9 | 18 | 9 |
| Sep 6, 2002 | Day | 5-5-6 | 16 | 7 |
| Sep 5, 2002 | Day | 9-5-0 | 14 | 5 |
| Sep 4, 2002 | Day | 2-7-1 | 10 | 1 |
| Sep 3, 2002 | Day | 8-3-6 | 17 | 8 |
| Sep 2, 2002 | Day | 3-7-8 | 18 | 9 |
| Sep 1, 2002 | Day | 2-2-2 | 6 | 6 |