The winning Vermont Pick 3 numbers for October 11, 1986 were: day 7-6-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 11, 1986 | Day | 7-6-6 | 19 | 1 |
| Oct 10, 1986 | Day | 0-6-0 | 6 | 6 |
| Oct 9, 1986 | Day | 2-4-0 | 6 | 6 |
| Oct 8, 1986 | Day | 3-6-5 | 14 | 5 |
| Oct 7, 1986 | Day | 8-6-8 | 22 | 4 |
| Oct 6, 1986 | Day | 1-6-6 | 13 | 4 |