The winning Texas Pick 3 numbers for December 5, 2006 were: day 3-6-7; night 1-8-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 5, 2006 | Night | 1-8-1 | 10 | 1 |
| Dec 5, 2006 | Day | 3-6-7 | 16 | 7 |
| Dec 4, 2006 | Night | 8-6-2 | 16 | 7 |
| Dec 4, 2006 | Day | 2-0-8 | 10 | 1 |
| Dec 2, 2006 | Night | 0-1-0 | 1 | 1 |
| Dec 2, 2006 | Day | 0-1-1 | 2 | 2 |
| Dec 1, 2006 | Night | 6-9-0 | 15 | 6 |
| Dec 1, 2006 | Day | 3-7-5 | 15 | 6 |
| Nov 30, 2006 | Night | 2-5-2 | 9 | 9 |
| Nov 30, 2006 | Day | 9-4-7 | 20 | 2 |
| Nov 29, 2006 | Night | 1-7-5 | 13 | 4 |
| Nov 29, 2006 | Day | 3-2-2 | 7 | 7 |