The winning Texas Pick 3 numbers for December 16, 2003 were: day 7-3-7; night 4-9-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 16, 2003 | Night | 4-9-9 | 22 | 4 |
| Dec 16, 2003 | Day | 7-3-7 | 17 | 8 |
| Dec 15, 2003 | Night | 6-3-6 | 15 | 6 |
| Dec 15, 2003 | Day | 7-9-1 | 17 | 8 |
| Dec 13, 2003 | Night | 2-1-7 | 10 | 1 |
| Dec 13, 2003 | Day | 8-4-9 | 21 | 3 |
| Dec 12, 2003 | Night | 1-7-9 | 17 | 8 |
| Dec 12, 2003 | Day | 5-4-2 | 11 | 2 |
| Dec 11, 2003 | Night | 8-9-5 | 22 | 4 |
| Dec 11, 2003 | Day | 3-8-9 | 20 | 2 |
| Dec 10, 2003 | Night | 2-0-8 | 10 | 1 |
| Dec 10, 2003 | Day | 1-6-8 | 15 | 6 |