The winning Texas Pick 3 numbers for December 4, 2003 were: day 4-5-3; night 1-7-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 4, 2003 | Night | 1-7-5 | 13 | 4 |
| Dec 4, 2003 | Day | 4-5-3 | 12 | 3 |
| Dec 3, 2003 | Night | 9-3-9 | 21 | 3 |
| Dec 3, 2003 | Day | 6-4-5 | 15 | 6 |
| Dec 2, 2003 | Night | 3-0-8 | 11 | 2 |
| Dec 2, 2003 | Day | 9-7-4 | 20 | 2 |
| Dec 1, 2003 | Night | 9-5-3 | 17 | 8 |
| Dec 1, 2003 | Day | 4-7-8 | 19 | 1 |
| Nov 29, 2003 | Night | 4-8-4 | 16 | 7 |
| Nov 29, 2003 | Day | 4-4-0 | 8 | 8 |
| Nov 28, 2003 | Night | 8-4-3 | 15 | 6 |
| Nov 28, 2003 | Day | 2-4-3 | 9 | 9 |